Find two consecutive even integers such that the sum of the larger and twice the smaller is
62.m

20, 22

Step-by-step explanation:

Consider the integers x and x+2 (they are consecutive and even)

(2x)+(x+2)=62

3x+2=62

3x=60

x=20

x+2=22

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²