Could anyone help me with this question please?

construction = divide the figure into two parts.

now we have triangle abd and bdc.

first calculate the area of abd.

area of triangle= 1/2×base ×height

area of triangle= 1/2×18×7.5

area of triangle=67.5cm²

second calculate area of bdc

area of triangle=1/2×15.6×11.7

area of triangle=91.26cm²

area of the figure=area of abd + area of bdc

area of the figure=67.5cm²+ 91.26cm²

area of figure=158.76 cm².

the answer is y = 11.54

hope this : )