A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 16 cm long and 4 cm wide. The diameter of each circle is the width of the rectangle. What is the area of the bookmark? Use 3.14 for π.

76.56sqcm

Step-by-step explanation:

Area of rectangle= length * width

= 16 * 4 = 64sqcm

Area of semicircle= (1/2)(r^2)π

r= d/2= 4/2= 2

Area of semicircle= (1/2)(2^2)(3.14)

= 6.28sqcm

Area of bookmark= Area of rectangle + 2*Area of semicircle

Area of bookmark= 64 + 2(6.28)

=64 + 12.56 = 76.56sqcm

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i