Given : A toy car is placed on the floor. Its movement details are given

Given :  A toy car is placed on the floor. Its movement details are given

To find : Distance covered by Car & graph to be plotted

Solution:

Start from rest

u = 0  at  t = 0

Constant acceleration for 3 sec reaching velocity 4 m/s

V = U +at

=> 4 = 0 +  a(3)

=>a = 4/3  m/s²

Distance here  S = ut + (1/2)at²

S = 0 + (1/2)(4/3)3²

=> S = 6 m

deceleration of 0.5 m/s² for 4 sec

=> v = 4  - (0.5)4

=> v = 2 m/s

Distance here   =  4(4)  - (1/2) (0.5)4²

= 16 - 4

= 12 m

Total Distance = 6 + 12 = 18 m

Total Distance traveled by toy Car = 18 m

Graph attached

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Step-by-step explanation:

associative property of multiplication