I really need help on this please

m<S = 92°

Step-by-step explanation:

Opposite angels of a cyclic quadrilateral are supplementary. That is, they sum up to 180°.

<S and <Q are opposite angles of the cyclic quadrilateral given.

m<Q = 88°

Therefore,

m<Q + m<S = 180°

88° + m<S = 180° (substitution)

m<S = 180° - 88° (substraction property of equality)

m<S = 92°

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.