01-Duas cargas pontuais positivas, Q1 = 23C, é colocada a uma distância r = 3,0 cm de outra carga também pontual, negativa, Q2 = -0,60_C.
Suponha que as cargas Qie Q2 estejam no ar, calcule o valor da
força F1 que Q2 exerce sobre Q1​

the bottom of the spinner is not flat.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.