Find the roots of the equation below. x2 - 6x + 12 = 0

-3 ± √3
3 ± √3
-3 ± i√3
3 ± i√3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra I

FactoringStandard Form: ax² + bx + c = 0Quadratic Formula:

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 6x + 12 = 0

Step 2: Identify Variables

Compare the quadratic to standard form.

x² - 6x + 12 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = 12

Step 3: Find Roots

Substitute in variables [Quadratic Formula]:                                               [Quadratic Formula] Simplify:                                                                       [Quadratic Formula] [√Radical] Evaluate exponents:                                 [Quadratic Formula] [√Radical] Multiply:                                                     [Quadratic Formula] [√Radical] Subtract:                                                     [Quadratic Formula] [√Radical] Factor:                                                       [Quadratic Formula] [√Radicals] Simplify:                                                   [Quadratic Formula] [Fraction - Denominator] Multiply:                             [Quadratic Formula] [Fraction - Numerator] Factor:                                   [Quadratic Formula] [Fraction] Divide:                                                        

< i think this is the answer unless i did my math wrong

Cbecause they are equal so that means it is the same on both sides? ! hope this