Find the slope of the line passing through each of the following pairs of points. (4,0) (-2,8)

Step-by-step explanation:

We know that,

slope=

(x

2

−x

1

)

(y

2

−y

1

)

Slope=

(0+4)

(0−0)

=0

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

may i see the picture? it would a lot, xox