The small piston of a hydraulic press has an area of 2.0 cm^2 and the large piston has an area of 16 cm^2. If the small piston has a force of 4.0 N applied to it, the output force of the large piston is ? A.) 0.50 N B.) 2.0 N C.) 8.0 N D.) 32 N

32N

Step-by-step explanation:

Given data

A1= 2cm^2

A2= 16cm^2

F1= 4N

F2=???

Applying the formula

Presure= force/area

P=F/A

F1/A1=F2/A2

substitute

4/2= F2/16

cross multiply

F2= (16*4)/2

F2= 64/2

F2= 32N

Hence the output force is 32N

its totaly b

your welcome btw

step-by-step explanation: