Find the following for the function f(x)= 3x2 + 4x - 3. (a) f(0)
(e) -f(x)
(b) f(3)
(f) f(x + 2)
(c) f(-3)
(g) f(3x)
(d) f(-x)
(h) f(x + h)

Step-by-step explanation:

a. -3

e. -3x^2 -4x +3

b 27+12-3= 36

f. 3(x+2)^2 + 4(x+2) -3

c. 27-12-3= 12

g. 3(3x)^2 + 4(3x) -3

d. 3x^2 -4x -3

h. 3(x+h)^2 + 4(x+h) -3

y do u put "subscirbe to ence" on a app for ppl who need with their work?

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752