The solution to which system of equations has a positive x value? a.) x + y = 0
3x - y = 2

b.) 3 - y = 2
y = -x - 2

c.)x + y = 0
3x - 3y = -6

d.)y = -x - 2
x + y = 0

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

but there’s no any figure there!