PLS I NEED HELP I ONLY HAVE 15 MINS I BEG YOU PLEASE!! :( In the year 1984 the average American used to eat 55.7 pounds of chicken. This was 2.8 pounds more than the the year 1982 average. By what percent did chicken consumption increase from the year 1982 to the year 1984?

To solve this, we need to use the z statistic. The formula for z score is:

z = (x – u) / s

where x is sample value = less than 90, u is the sample mean = 90.6, s is the standard deviation = 17.2

z = (90 – 90.6) / 17.2

z = -0.035

From the standard distribution tables:

P (z = -0.035) = 0.4860

Therefore there is about 48.60 % chance that it will be less than 90 pounds

I think it increased by 0.05.

Step-by-step explanation:

If you subtract 2.8 from 55.7 you'll get 52.9. So I would divide 55.9 by 52.9 and get 1.05. I then would subtract 1.0

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3