The average age at which adolescent girls reach their adult height is 16 years. Suppose you have a sample of 27 adolescent girls who are developmentally delayed, and who have an average age at which they reached their adult height of 17.1 years and a sample variance of 36.0 years. You want to test the hypothesis that adolescent girls who are developmentally delayed have a different age at which they reached their adult height than all adolescent girls. Calculate the t statistic. To do this, you first need to calculate the estimated standard error. The estimated standard error is SM= .The t statistic is . Now suppose you have a larger sample size n 81. Calculate the estimated standard error and the t statistic for this sample with the same sample average and the same standard deviation as above, but with the larger sample size. The new estimated standard error is .The new t statistic is

a) t-statistic  t = 0.9532

b) The standard error  S.E = 1.2

c) The new  t-statistic = 1.95

d)  The new estimated standard error =0.666

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 16

The sample size n=27

The mean of the sample = 17.1

Given that the variance of the sample (S²) = 36.0

The standard deviation of the sample (S) = √36 = 6

Test statistic

t = 0.9532

b)

   The standard error is defined by

Step(ii):-  

c) given that the sample size n = 81

Test statistic

t = 1.65

d)

The new standard error is defined by

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2