Please help me with geometry question :)

Given:

The graph of a triangle ABC.

A line is parallel to AC and passes through the point D.

To find:

The point at which the intersection of this parallel line be with the line BC.

Solution:

From the given figure it is clear that A(1,7), B(9,7), C(9,1) and D(5,7).

Slope of AC is

Slope of parallel lines are same. So, the slope of parallel line is also .

The parallel line passes through D(5,7) with slope . So, the equation of the line is

             ...(i)

From the given graph it is clear that the line BC is a vertical line. So, the x-coordinates of all the points lie on BC are the same, i.e., 9.

Putting x=9, we get

Therefore, the point at which the intersection of this parallel line be with the line BC is (9,4).

answer

step-by-step explanation:

shorter then the tree