What must be added to each term of the ratio 3:5, so that it becomes 4:5​

5 must be added to both the terms to get the ratio 4:5.

Step-by-step explanation:

(3+x)/(5+x)=4/5

Therefore,

15+5x=20+4x

=5x-4x=20-15

=x=5

I hope it's helpful!

3+y/5+y=4/5

let y be the no.to be added

5(3+y)=4(5+y)

15+5y=20+4y

-5= -y

y=5

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.