A triangular flower bed with sides 11 ft, 13 ft and 17 ft is filled 2 feet deep with compost that has a density of 13.2 lbs/ft2. How much willthe compost weigh that fills this flower bed?

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↓Answer↓

The length of a Triangular flower bed is 11 ft. less than 3 times its width. The area of the bed is 20ft^2. Find the dimensions of the flower bed.

let width be x

three times width =3x

length = 3x-11

x(3x-11)=20

3x^2-11x-20=0

3x^2-15x+4x-20=0

3x(x-5)+4(x-5)=0

(3x+4)(x-5)=0

x=5 width

width is 5 feet

length = 3x-11

=3*5 -11

=4 feet length

Hope this helped ya!

☁floofy-cloud☁

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068