Ming's school is selling tickets to a play. On the first day of ticket sales the school sold 8 adult tickets and 1 student ticket for a total of $95. The school took in $71 on the second day by selling 2 adult tickets and 7 student tickets. Define two variables for this situation. Write a system of equations to represent this situation. What is the price each of one adult ticket and one student ticket?

Your answer.

8x + y = 95(1)

2x + 7y = 71 (2)

Y = 95-8x (3)

Put this value in eq 2

Then x = 11

Put x value in eq 3

Y = 7

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Step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.