22 foot ladder is placed against a vertical wall of building with the bottom of the ladder standing on level ground 9 feet from the base of the building how high up the wall does the ladder reach

20.1 feet

Step-by-step explanation:

We solve the above question using the Pythagoras Theorem

The Pythagoras Theorem =

Opposite² + Adjacent ² = Hypotenuse²

From the above question,

Opposite side = Height of the wall = x

Adjacent side = Distance from the base of the building = 9 feet

Hypotenuse = Length of the ladder = 22 feet

Hence:

x² + 9² = 22²

x² = 22² - 9²

x = √22² - 9²

x = √403

x = 20.0748599 feet

Approximately = 20.1 feet

Therefore, the height of the wall = 20.1 feet

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step-by-step explanation:

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to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk