1) a + b + a +b= 2) 52 + + +52 + 2+ + s2 D

3) 5z + 2y + 7z3

4) 5m2 + 3n + 2m2 + n=

5) 3p + 30 + 39 + 5p -20 + q=

6) 5x2y - 9x2y + 7x²y - x2y=D

7) 2x3 - X2 - 5x2 - 7x3 - 3x2=

8) -5a - 3a + 4a - 8a -4=

9) 6x3 – 4x2 - 5x + x2=

10) -7x2 - 9x + 6x – x2=

11) 4 + x- 5x - 7x + 6- 9x=

12) -4x2 - 5x3 + 7x2 - X3 + 4x2 -8x3=

13) -9x - x - 8x – 15x – 10x – 2x=

14) 11x + x2 - 9x + 8x2 – 14x2 - 7x - 19x2=

15) 8 - 6x + 5x -9-11x-6-14x - 4=

16) x2 – 4x - 8x + 7x2 – 5 - 12x2 - 2 + x=

17) -4x2 – 7x2 - 5x + 11x - 2x2 + 8x - 3x2=

18) -9x + 4x2 – 5x + x2 - x - x - x2=

19) -8 - 5x - 7x - 6x - x- 6 + 4=

20) -9y – 4y + 5x - 7x - y + 8x - 2y=​

3728827272-28277372

c

293728272

e

38838373828737

l

83826382

o

82372882

a

283638272

d

726372826

v

282882

e

2928292282828

r

282828272727272772

t

727263826282728

y

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

the answer is d

step-by-step explanation: