(05.04 LC) A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey results for the first second and third period classes are as follows:
First period: 2.4 3.1.0.2.1.3.1.4. 9.2.4 3.0
Second period: 3.2.3.1.3.4.2.4.3.1.0.2.3.12
Third period 4.5.3.4.2.3.4 18.2.3.1.0.2 1.3
Which is the best measure of center for first period, and why?
Mean because there are no others that affect the center
Median because there is one outer that affects the center
Interquartile range, because there is one other that affects the center
Standard deviation because there are no others that affect the center

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )