the equation for line p can be written as y= -9x +5. line q is perpendicular to line p and passes through (-9, 2). what is the equation of line q?​

y=mx+b where m is the slope and b is the y intercept

y=-9x+5 so the slope is -9 for lines to be perpendicular

m1(m2)=-1 so the line q will have a slope -9m=-1, m=1/9 so

q=x/9+b, using point (-9,2) we can solve for b

2=-9/9+b

2=-1+b

b=3 so

q=x/9+3, or more neatly

q=(x+27)/9

associative property hopes this ! : )

step-by-step explanation:

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