Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is measured in meters, and the variable t is measured in seconds. The equation describing the graph of the position of the first object with respect to time is d = 2.5t + 2.2. The graph of the position of the second object is a parallel line passing through (t = 0, d = 1). What is the equation of the second graph? A.
d = 2.5t + 1

B.
d = t + 2.5

C.
d = -0.4t + 1

D.
d = 2.5t + 3.2

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A)   d = 2.5t+1

The equation of the second graph d = 2.5t+1

Step-by-step explanation:

Explanation:-

Given equation describing the graph of the position of the first object with respect to time is d = 2.5t + 2.2.

Given that the point ( t=0,d=1)

The parallel line to the given line

                                          d = 2.5t +k ...(i)

The equation (i) passes through the point  ( t=0,d=1)

                                          1   = 2.5(0) +k

                                           k =1

The equation of the parallel line

                                     d = 2.5t + 1

question:

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