The school yard is twice as long as it is wide. The width is 23 yards. How much fencing is needed to enclose the school yard?

138ft

Step-by-step explanation:

w = 23, h = 46

23 × 2 = 46

23 + 23 + 46 + 46 = 138

138ft is needed

good luck, hope this helps :)

Step-by-step explanation:

P=2(L+W) and we are told L=2W so

P=2(2W+W)

P=2(3W)

P=6W and we are told W=23 yd so

P=6(23)

P=138 yd

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.