Correct answer gets BRAINLIEST

confusing

Step-by-step explanation:

im bad at math :<

f(x)/g(x)

(x2-1)/(x-1)

x cannot equal 1 because this would render the denominator, also known as the divisor, as zero.

x can be greater than 1.

If you would like, we can factor the numerator...

x2-1

(x+1)(x-1)

FIRST...(x)(x)=x2

OUTER...(x)(-1)=-1x=-x

INNER...(1)(x)=1x=x

LAST...(1)(-1)=-1

x2-x+x-1

x2-1

So...

f(x)/g(x)=[(x+1)(x-1)]/(x-1)

(x-1) is in the numerator and denominator.  It cancels...

f(x)/g(x)=(x+1)