A cell phone costs $750 and loses 28% of its value each year. What is the value of the phone after 2 years? 1. $216.54
2. $388.80
3. $1228.80
4. $456.30

Initial costs 750 and loses .28 of value each year, so still worth 1-.28=.72 of value at start of next year. 750*(.72)^n is the value after n years since for n=0, new, it is 750*.72^0=750*1=750, and after 1 year it is worth 750*.72^1=750*.72 means it lost 28% value after one year. If you with to express it as an exponential exp(..) you need to convert the .72^n into exp(log(.72)*n)=exp(-.3285*n) so you get

750*exp(-.3285*n) as the value after n years.

388

Step-by-step explanation:

first year it loses 210

750×.28=210

second year phone value is 540

540×.28=151.2

third year phone value is 388

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

15 batches are the most you can make

step-by-step explanation: