PLS ANSWER WILL GIVE 10 PTS The perimeter of a parallelogram is 164 cm. The diagonals intersect one another at 90°. One diagonal is bisected into segments of lengths 1500/x + 10 and x − 10 cm. Determine the length of the shorter diagonal.

a) 50 cm
b) 18 cm
c) 41 cm
d) 9 cm

Work Shown:

Since the parallelogram has perpendicular diagonals, this means that we're dealing with a rhombus. A rhombus has all four sides equal to one another.

One diagonal is bisected, or cut in half, to form the smaller pieces of length (150/x) + 10 and x-10. Set these two expressions equal to each other and solve for x

(150/x) + 10 = x-10

1500/x = x-10-10

1500/x = x-20

1500 = x(x-20)

1500 = x^2-20x

0 = x^2-20x-1500

x^2-20x-1500 = 0

(x-50)(x+30) = 0

x-50 = 0 or x+30 = 0

x = 50 or x = -30

We'll ignore the negative x value as it leads to a negative length which doesn't make sense.

If x = 50, then  

Each piece of this diagonal is 40 cm long.

The two smaller pieces combine to 40+40 = 80, which is the length of one of the diagonals. If this was the shorter diagonal, then 80 would be listed as part of the answer choices. However, 80 is not one of the answers.

Note how the two diagonals of the rhombus cut the figure into four right triangles.

Each right triangle has one known leg to be 40 and an unknown leg of y. The hypotenuse is 164/4 = 41 since we divide the perimeter by the four equal sides of the rhombus.

We'll use the pythagorean theorem to find the value of y

a^2 + b^2 = c^2

40^2 + y^2 = 41^2

1600 + y^2 = 1681

y^2 = 1681-1600

y^2 = 81

y = sqrt(81)

y = 9

This represents half of the other diagonal, so the full length of this other diagonal is 2*9 = 18 cm.

b) 18 cm

Step-by-step explanation:

happy to help ya :)

maybe showing the graph would

step-by-step explanation:

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