Can someone help asap ill give brainiest plus 50 points if you answer right. Examine the following graph of a nonlinear function.
Graph of a nonlinear function passing through (0, negative 3), (1, negative 2), (2, 0), & (3, 4).

What is the average rate of change over the interval 1≤x≤3?

Enter your answer as a number, like this: 42

2

Step-by-step explanation:

To find average rate of change

Find the change of y in divided over change in x.

Do all the points from x=1 to x=3.

When x=1, y=-2

When x=2, y=0

The change of y is 2 and the change in x is 1 so

12.5 feet

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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