What is an equation of the line that passes through the point (-6,-2)(−6,−2) and is parallel to the line 3x-2y=23x−2y=2

y = 3/2x + 7

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is 3x - 2y = 2. First, let's put this into standard form.

3x - 2y = 2

Add 2y to both sides to make y positive.

3x = 2y + 2

Subtract 2 from both sides to isolate y.

3x - 2 = 2y

Isolate y further by dividing both sides by 2.

3/2x - 1 = y or y = 3/2x - 1

This is now your first line. Its slope is 3/2. A line parallel to this one will also have a slope of 3/2.

Plug this value (3/2) into your standard point-slope equation of y = mx + b.

y = 3/2x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-6, -2). Plug in the x and y values into the x and y of the standard equation.

-2 = 3/2(-6) + b

To find b, multiply the slope and the input of x (-6)

-2 = -9 + b

Now, add 9 to both sides to isolate b.

7 = b

Plug this into your standard equation.

y = 3/2x + 7

This equation is parallel to your given equation (y = 3/2x - 1) and contains point (-6, -2)

Hope this helps!

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

your answer is d 2,500

step-by-step explanation: