A room has a perimeter of 40 feet. The length is 4 less than 2 times the width. What are the dimensions of the room?

First, develop an equation for this scenario. The formula to find the perimeter of a quadrilateral is 2l+2w. Because the length is 4 less than twice the width, this would be translated to (2w-4). Plug this into the variable for the length to get 2(2w-4)+2w=40. Distribute the 2 to get 4w-8+2w=40. Add the like terms to get 6w-8=40. Add 8 to both sides and get 6w=48. Divide 6 to result with w=8.

Now that we know w, we can substitute 8 into the variable to solve for the length. 2l+2(8)=40. Multiply 8 and 2 to get 2l+16=40. Subtract 16 to both sides to get 2l=24. Divide 2 to both sides to result with l=12.

Length = 12 feet

Width = 8 feet

okay wait before i answer, is this for your points on a graph?

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)