y=-\dfrac{4}{3}x+8y=β
Mathematics, 17.02.2021 03:10 vallhernandez13
I have no idea how to solve this
I'm in 8th grade btw
y=-\dfrac{4}{3}x+8y=β
3
4
β
x+8y, equals, minus, start fraction, 4, divided by, 3, end fraction, x, plus, 8.
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I have no idea how to solve this
I'm in 8th grade btw
y=-\dfrac{4}{3}x+8y=β
y=-\dfrac{4}{3}x+8y=β
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