In an old story, a man puts 2 grain of rice on the first space of a chessboard. He puts 4 grains on the third space and so on write and evaluate an expression with exponents to find how many grains of rice the man puts on the tenth space.

11

Step-by-step explanation:

From the question,

a = first term= 2

3rd term = a + 2d = 4

2 + 2d = 4

2d = 4-2

2d = 2

Commons difference = d = 2/2 = 1

10th term = a + (n-1)d = a + (10-1)d = a + 9d

= 2 + 9(1)

= 2 + 9

= 11

The 10th term is 11

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