Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections select the true statement

Model B has 6 shaded sections

Step-by-step explanation:

The question is not complete. The complete question should be in the form:

Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.

Solution:

The fraction modeled by model A is given by the ratio of shaded sections to  the total number of sections.

That is Fraction of model A = number of shaded sections / total number of sections.

Hence:

Fraction of model A = 3 / 6

Since model B and Model A are equivalent, the number of shaded sections in Model A is given by:

number of shaded sections in model B/ total number of sections in model B =  Fraction of model A

number of shaded sections in model B / 12 = 3 / 6

number of shaded sections in model B = 12 * 3/6

number of shaded sections in model B = 6

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

two data sets with the same median will not have the same varaibility

step-by-step explanation: