Anyone know how to do this?

third option

Step-by-step explanation:

The equation of quantities in direct variation is

y = kx ← k is the constant of variation

y = 3x ← is in this form with k = 3

Thus the function represents direct variation → I

The graph of the equation of direct variation passes through the origin II

When x = 2, then

y = 3 × 2 = 6 → IV

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3