Line p passes through points (6, 8) and (2, 11). Line q is perpendicular to p. What is the slope of line q?

Step-by-step explanation:

Slope of p=

                 = -

∵line q is perpendicular to p

∴Slope of q x slop of p=-1

Slope of line q=

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i