Mathematics, 16.02.2021 07:30 luhmama
(Easy) An object is launched at 19.6 meters per second (m/s) from a 5.58 meter tall platform. The equation for the object’s height s at time t seconds after launch is s(t) = 4.9t^2 + 19.6t + 58.8s(t) = -4.9^2 + 19.6t + 58.8, where s is in meters. How high will the object be after 5 seconds?
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(Easy) An object is launched at 19.6 meters per second (m/s) from a 5.58 meter tall platform. The eq...
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