HELP ME PLEASE Marcla shoots an arrow that hits a bull's-eye 80 feet away. Before hitting the bull's-eye, the arrow reaches a

maximum height of 16 feet at the midway point, 40 feet.

Part 1 out of 2

If the bull's-eye is considered to be at (80, 0), what function (In Intercept form) could represent the path of

the arrow If x is the horizontal distance from Marcia and h(x) represents the height of the arrow in relation

to the horizontal distance?

The function is h(x)=

Next

See answer below

Step-by-step explanation:

In this case, we can assume that this function follows a linear function. In this case, the general expression would be:

y = a + bx

Where:

a: Y intercept

b: slope of the function

To get the slope we need to apply the following expression:

b = y₂ - y₁ / x₂ - x₁

We already have two points, (80,0) and (40,16) from here, we can determine the slope:

b = 16 - 0 / 40 - 80

b = -16/40

b = -2/5

Now that we know the slope, we can determine the y-intercept if it have:

a = y - bx

Using any point, we can calculate it:

a = 0 - (-2/5*80)

a = 0 + 160/5

a = 32

With these two values, we can write the function:

Hope it helps