Entry to a certain University is determined by a national test. The scores on this test are known to be normally distributed with a mean of 725 and a standard deviation of 115. Harriet wants to be admitted to this university and she knows that she must score better than at least 75% of the students who took the test. Harriet takes the test and scores 874.5. 1. (2pts) What percentile did Harriet score in? 2. (2pt) Will Harriet be admitted? Wh

She scored in the 90th percentile.

90th percentile is better than 90% of the students who took the test, so yes, she will be admitted.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The scores on this test are known to be normally distributed with a mean of 725 and a standard deviation of 115.

This means that

She must score better than at least 75% of the students who took the test.

So her z-score should have a pvalue of at least 0.75.

Harriet takes the test and scores 874.5. 1. (2pts) What percentile did Harriet score in?

We have to find the pvalue of Z when X = 874.5.

has a pvalue of 0.9032

She scored in the 90th percentile.

Will Harriet be admitted?

90th percentile is better than 90% of the students who took the test, so yes, she will be admitted.

but which class are u may know that first