g Over the long term, a continuous-time Markov chain on t1, 2, 3, 4u spends 10% of the time in state 1, and 30% of the time each in state 2, 3, and 4, respectively. Moreover, from any state i P t1, 2, 3, 4u, it stays on average i minutes before moving to a new state. (a) Find the stationary distribution of the continuous-time chain. (b) Find the stationary distribution of the embedded discrete-time chain.

jml angle lkj & angle mj = lm

answer: idk wbu

step-by-step explanation: umm..

step-by-step explanation:

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours