Suppose a certain character in a role-playing game has an ability to use in battles. When activated, the ability deals damage to an enemy using X hits, where X is a random variable with the following cumulative distribution function The chance of getting between 2 and 4 hits is 0.46 . The chance of getting exactly 3 hits is

The chance of getting exactly 3 hits is =  0.20

Step-by-step explanation:

P.S - The exact question is -

As given,

F(x) = 0 ,          x < 1

         0.30 ,     1  ≤ x < 2

         0.56 ,     2 ≤ x < 3

         0.76 ,     3 ≤ x < 4

         0.9 ,       4  ≤ x < 5

         1 ,            5  ≤ x

Now,

f(x) = 0.30 ,                            x = 1

        0.56 - 0.30 = 0.26 ,     x = 2

         0.76 - 0.56 = 0.20 ,     x=3

         0.9 - 0.76 = 0.14  ,       x = 4

         1 - 0.9 = 0.1 ,                 x = 5

          0,                                 otherwise

Now,

The chance of getting exactly 3 hits is = f(x = 3) = 0.20

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah