ABCD is a rhombus. Given only the choices below, which properties would you use to prove AEB ≅ DEC by SAS? The diagonals are ⊥ to each other.

The diagonals bisect each other.

Opposite sides are | |.

All sides are congruent.

The diagonals bisect each other.

Step-by-step explanation:

Given

Rhombus ABCD

Required

Which property proves AEB ≅ DEC by SAS

From the question, we understand that the property is to be proved by SAS; SAS implies that Side-Angle-Side

We can assume that point E is where the diagonals meet.

So, we have:

Equal sides: AE = DE and BE = CD

Equal angle: <E = <E

The above implies that the diagonals bisect one another.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.