Aubrey invested $61,000 in an account paying an interest rate of 1.9% compounded continuously. Assuming no deposits or withdrawals are made, how long would it take, to the nearest tenth of a year, for the value of the account to reach $73,600?

9.9 years.

Step-by-step explanation:

If interest is compounded continuously, then formula to compute final amount A = , where P =initial amount, r= rate of interest , t=time.

Given: P= $61,000, r= 1.9% =0.019  , A = $ 73600

Substitute all values in formula

Taking natural log on both sides

Hence, the required time = 9.9 years.

thus, the first answer choice, y = sec x, is the correct one