Mathieu grows specialty tomatoes that are much larger than typical tomatoes. The distribution of their weights is strongly skewed to the left with a mean of 232 g and a standard deviation of 12 g. Suppose we were to calculate the mean weight from a random sample of 16 of Mathieu's tomatoes. We can assume independence between tomatoes in the sample. What is the probability that the mean weight from the sample of 16 tomatoes T is within 6 g of the population mean? A. P(226 < 5 < 238) — 0.38
B. P(226<ī <238) 0.45
C. P(226 < i <238) 0.88
D. P(226 < T <238) 0.95
E. We cannot calculate this probability because the sampling distribution is not normal.

E. We cannot calculate this probability because the sampling distribution is not normal.

Step-by-step explanation:

Probability may be defined as how likely something is going to take place. It is concern with the numerical description of an even to occur likely.

In the context, the sampling distribution is normal when the sample size is generally greater than 30 (thirty).

But for sample size of 16 tomatoes, it is not normal. Therefore, we cannot find out the probability of the mean weight of 16 tomatoes as the sampling distribution is not normal.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.