Given that the 11th term of arithmetic progression is 43 that the first term is 3 find the 4th term​

15

Step-by-step explanation:

The 11th term of arithmetic progression is 43. We can use this to get the common difference which will be:

a + (n - 1)d = 43

where,

a = first term = 3

n = nth term = 11

d = common difference = unknown

Therefore, a + (n - 1)d = 43

3 + (11 - 1)d = 43

3 + 10d = 43

10d = 43 - 3

10d = 40

d = 40/10

d = 4

Common difference = 4

Therefore, 4th term will be:

= a + (n - 1)d

= a + (4-1)d

= a + 3d

= 3 + 3(4)

= 3 + 12

= 15

The 4th term is 15

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: