The midpoint of line segment RT is at (3.5, 2). If R is at (-3, 7), what are the coordinates of T?

(10,-3)

Explanation :

We know ,

If R (x1,y1)=(-3,7)

If T (x2,y2) = ?

Midpoint of line RT = (-3+x2)/2 , (7+y2)/2

(3.5,2) = (-3+x2)/2 , (7+y2)/2

So,

3.5 = (-3 + x2)/2 |1|

2 = (7 + y2)/2 |2|

Now , From eqn. |1|

3.5×2 = -3 + x2

7 + 3 = x2

10 = x2

From eqn. |2|

2×2 =7 + y2

4 - 7 = y2

-3 =y2

So,

T (x2,y2) = (10,-3)

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: