The average amount of money spent for lunch per person in the college cafeteria is $6.77 and the standard deviation is $2.51. Suppose that 42 randomly selected lunch patrons are observed. Assume the distribution of
money spent is normal, and round all answers to 4 decimal places where possible.
a. What is the distribution of X? X - N
b. What is the distribution of ? - Nd
c. For a single randomly selected lunch patron, find the probability that this patron's lunch cost is between
$6.9291 and $7.3228.
d. For the group of 42 patrons, find the probability that the average lunch cost is between $6.9291 and
$7.3228.
e. For part d), is the assumption that the distribution is normal necessary? Yes No
Hint:
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where r the answers

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

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i'm sorry, what's your question here?