The length of a rectangle is 4 inches longer than it is wide. If the perimeter is 52 inches, what are the dimensions of the rectangle?

L = 15

W = 11

Step-by-step explanation:

P = 2L + 2W

2L + 2W = 52                         Divide each term by 2

2L/2 + 2W/2 = 52/2

L + W = 26                              Substitute the value for L

W + 4 + W = 26                      

2W + 4 = 26

2W = 26 - 4                            Subtract 4 from both sides

2W = 22                                  Divide by 2

W = 22 /2

W = 11

L = W + 4

L = 11 + 4

L = 15

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."