The sides of a triangle formed a geometric progression with a ratio r. For what values of r, it is possible?

ok so i really shouldnt get points for this, but i wanted to help. The person who solved the problem here:  https://math.stackexchange.com/questions/2911546/suppose-the-sides-of-a-triangle-form-a-geometric-progression-with-common-ratio-r     is correct, but it is not very clear. Basically, he rounded to the third decimal point (since a sqrt has infinate decimals), and this might have been what got you the wrong answer. Basically the important thing is that r has to be between the (-1+√5)/2 and (1+√5)/2, or (-1+√5)/2 < r < (-1+√5)/2

isi

step-by-step explanation:

use that smart brain

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)