Graph a sine function whose amplitude is 4, period is π , midline is y=−3, and y-intercept is (0, −3). The graph is not a reflection of the parent function over the x-axis. Use the sine tool to graph the function.

The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

y=4sin(2x) - 3

Step-by-step explanation:

Recall the form of a sinusoidal function is Asin(Bx + C) + D, where A is the amplitude, B is the frequency (could also be viewed as the period), C is the horizontal (phase) shift, and D is the vertical shift. Also, recall sin(x) has a period of 2π.

You start with the parent function (sin(x)).

Then, knowing the amplitude is 4: 4sin(Bx + C) + D

Then, knowing the period of the regular sine function is 2π, to get to a period of π, divide by 2 (the period of the curve changes by a factor of 1/2), so your B coefficient is 2: 4sin(2x + C) + D

There is no phase shift, so omit C: 4sin(2x) + D

Since the midline is y = -3, that is your vertical shift (D): 4sin(2x) - 3

Graph of y = 4sin(2x) - 3 is below:

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

people grow faster than other people.

step-by-step explanation:

should you really be posting this isn't math boi.