A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,156,400 from each​ sold-out event. How many seats does each section​ hold?

Section A holds 27500 , Section B has 14100 and SEction C has 13400.

Step-by-step explanation:

Let x= Number of seats in section A.

y = Number of seats in section B.

z= NUmber of seats in sectionC.

As per given , we have

x+y+z=55000           (i)

x= y+z                (ii)

28x+16y+12z=1156400          (iii)

Substitute value of x from (ii) in (i), we get

From (i)

From (iii), we get

Multiply 3 to (iv), we get

Eliminate (v) from (iv), we get

from (iv)

Hence, Section A holds 27500 , Section B has 14100 and SEction C has 13400.

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6