Find the area of an isosceles right triangle having the hypotenuse of length 30cm. ​

x = 3 ± √(5+y)

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629